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Lim. sin 3x/2x . tan 5x/3x, x->0

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Lim. sin 3x/2x . tan 5x/3x
x->0​

 

Jawab:

limit trigonometri

\sf lim_{x\to 0}~ \dfrac{sin~ 3x}{2x} . \dfrac{tan ~5x }{3x}

\sf = lim_{x\to 0}~ \dfrac{sin~ 3x}{2x} . lim_{x\to 0} \dfrac{tan ~5x }{3x}

\sf = \dfrac{3}{2} . \dfrac{5 }{3} = \dfrac{5}{2}


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